Question-148532

Question Number 148532 by cherokeesay last updated on 28/Jul/21

Answered by mr W last updated on 29/Jul/21

Commented by mr W last updated on 29/Jul/21

R = 6 c m

D G = \sqrt{2} r + r = R

\Rightarrow r = \frac{R}{\sqrt{2} + 1} = (\sqrt{2} - 1) R

D F = \frac{R}{\sqrt{2}} = \frac{\sqrt{2} R}{2}

C F = D F - \sqrt{2} r = \frac{\sqrt{2} R}{2} - (2 - \sqrt{2}) R = (\frac{3 \sqrt{2}}{2} - 2) R

A F = \sqrt{r^{2} - {(\frac{3 \sqrt{2}}{2} - 2)}^{2} R^{2}}

A F = R \sqrt{{(\sqrt{2} - 1)}^{2} - {(\frac{3 \sqrt{2}}{2} - 2)}^{2}}

A F = \frac{1}{2} R \sqrt{16 \sqrt{2} - 22}

A B = 2 A F = \sqrt{16 \sqrt{2} - 22} R \approx 0.792 R \approx 4.753

Commented by cherokeesay last updated on 29/Jul/21

I w o u l d a l s o l i k e t o s h a r e m y s o l u t i o n!

t h a n k y o u a l o t m r W!

Commented by Tawa11 last updated on 29/Jul/21

Nice sir . Thanks .

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