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Question-148917




Question Number 148917 by DELETED last updated on 01/Aug/21
Answered by DELETED last updated on 01/Aug/21
R_(s2) =16+4+5=25 Ω  i_(total) =(V/R_(s2) )=((12.5)/(25)) = 0.5 A  i_(total) =i_p =0.5 A  V_p =i_p ×R_p =0.5×4=2 vol
$$\mathrm{R}_{\mathrm{s2}} =\mathrm{16}+\mathrm{4}+\mathrm{5}=\mathrm{25}\:\Omega \\ $$$$\mathrm{i}_{\mathrm{total}} =\frac{\mathrm{V}}{\mathrm{R}_{\mathrm{s2}} }=\frac{\mathrm{12}.\mathrm{5}}{\mathrm{25}}\:=\:\mathrm{0}.\mathrm{5}\:\mathrm{A} \\ $$$$\mathrm{i}_{\mathrm{total}} =\mathrm{i}_{\mathrm{p}} =\mathrm{0}.\mathrm{5}\:\mathrm{A} \\ $$$$\mathrm{V}_{\mathrm{p}} =\mathrm{i}_{\mathrm{p}} ×\mathrm{R}_{\mathrm{p}} =\mathrm{0}.\mathrm{5}×\mathrm{4}=\mathrm{2}\:\mathrm{vol} \\ $$$$ \\ $$

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