Question Number 149107 by hama last updated on 03/Aug/21
Answered by hama last updated on 02/Aug/21
Commented by physicstutes last updated on 03/Aug/21
$${W}={Fd}\:\Rightarrow\:{F}\:=\:\frac{{W}}{{d}} \\ $$$$\therefore\:\frac{{U}}{{x}}\:=\:\mathrm{15}{x}−\mathrm{10}{x}^{\mathrm{2}} \\ $$$$\Rightarrow\:{F}\left({x}\right)\:=\:\mathrm{15}{x}−\mathrm{10}{x}^{\mathrm{2}} \\ $$