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Question-149331




Question Number 149331 by Samimsultani last updated on 04/Aug/21
Commented by john_santu last updated on 04/Aug/21
may be x=((7+(√5)))^(1/3)  −((7−(√5)))^(1/3)
$$\mathrm{may}\:\mathrm{be}\:\mathrm{x}=\sqrt[{\mathrm{3}}]{\mathrm{7}+\sqrt{\mathrm{5}}}\:−\sqrt[{\mathrm{3}}]{\mathrm{7}−\sqrt{\mathrm{5}}}\: \\ $$
Commented by amin96 last updated on 04/Aug/21
  Wrong entry
$$ \\ $$Wrong entry
Answered by MJS_new last updated on 04/Aug/21
x=0
$${x}=\mathrm{0} \\ $$

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