Question Number 149377 by fotosy2k last updated on 05/Aug/21
Answered by john_santu last updated on 05/Aug/21
$$\:\underset{\mathrm{n}\rightarrow\infty} {\mathrm{lim}}\frac{\mathrm{3}.\mathrm{3}^{\mathrm{n}} }{\mathrm{3}^{\mathrm{n}} \left(\mathrm{1}+\left(\frac{\mathrm{2}}{\mathrm{3}}\right)^{\mathrm{n}} \right)}=\underset{\mathrm{n}\rightarrow\infty} {\mathrm{lim}}\frac{\mathrm{3}}{\mathrm{1}+\left(\frac{\mathrm{2}}{\mathrm{3}}\right)^{\mathrm{n}} }=\mathrm{3} \\ $$
Commented by fotosy2k last updated on 05/Aug/21
$${thank}\:{you} \\ $$$$ \\ $$