Question Number 149383 by fotosy2k last updated on 05/Aug/21
Commented by fotosy2k last updated on 05/Aug/21
$${please}\:{help}\:{me} \\ $$
Answered by Ar Brandon last updated on 05/Aug/21
$$\frac{\mathrm{2}{n}+\mathrm{3}}{\mathrm{5}{n}+\mathrm{1}}=\frac{\mathrm{2}}{\mathrm{5}}\centerdot\frac{\mathrm{5}{n}+\frac{\mathrm{15}}{\mathrm{2}}}{\mathrm{5}{n}+\mathrm{1}}=\frac{\mathrm{2}}{\mathrm{5}}\centerdot\frac{\mathrm{5}{n}+\mathrm{1}+\frac{\mathrm{13}}{\mathrm{2}}}{\mathrm{5}{n}+\mathrm{1}} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:=\frac{\mathrm{2}}{\mathrm{5}}+\frac{\mathrm{13}/\mathrm{5}}{\mathrm{5}{n}+\mathrm{1}},\:\mathrm{divergent} \\ $$
Commented by fotosy2k last updated on 05/Aug/21
$${thank}\:{you} \\ $$