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Question-149623




Question Number 149623 by DELETED last updated on 06/Aug/21
Answered by DELETED last updated on 06/Aug/21
R_s =R_1 +R_2 =2+2=4 Ω  I_s =(V/R_s ) = (6/4) = 1.5 volt  karena hubungan seri   sifat=I_s =I_R_1  =I_(R2) =1.5 volt
$$\mathrm{R}_{\mathrm{s}} =\mathrm{R}_{\mathrm{1}} +\mathrm{R}_{\mathrm{2}} =\mathrm{2}+\mathrm{2}=\mathrm{4}\:\Omega \\ $$$$\mathrm{I}_{\mathrm{s}} =\frac{\mathrm{V}}{\mathrm{R}_{\mathrm{s}} }\:=\:\frac{\mathrm{6}}{\mathrm{4}}\:=\:\mathrm{1}.\mathrm{5}\:\mathrm{volt} \\ $$$$\mathrm{karena}\:\mathrm{hubungan}\:\mathrm{seri}\: \\ $$$$\mathrm{sifat}=\mathrm{I}_{\mathrm{s}} =\mathrm{I}_{\mathrm{R}_{\mathrm{1}} } =\mathrm{I}_{\mathrm{R2}} =\mathrm{1}.\mathrm{5}\:\mathrm{volt} \\ $$

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