Question Number 149628 by DELETED last updated on 06/Aug/21
Answered by DELETED last updated on 06/Aug/21
$$\frac{\mathrm{1}}{\mathrm{R}_{\mathrm{p}} }\:=\frac{\mathrm{1}}{\mathrm{R}_{\mathrm{1}} }+\frac{\mathrm{1}}{\mathrm{R}_{\mathrm{2}} }\:=\frac{\mathrm{1}}{\mathrm{6}}\:+\frac{\mathrm{1}}{\mathrm{3}} \\ $$$$\:\:\:\:\:\:=\frac{\mathrm{1}}{\mathrm{6}}\:+\:\frac{\mathrm{2}}{\mathrm{6}}\:=\frac{\mathrm{3}}{\mathrm{6}}\:\rightarrow\mathrm{R}_{\mathrm{p}} =\frac{\mathrm{6}}{\mathrm{3}}=\mathrm{2}\Omega \\ $$$$\mathrm{I}_{\mathrm{p}} =\frac{\mathrm{V}}{\mathrm{R}_{\mathrm{p}} }=\frac{\mathrm{3}}{\mathrm{2}}\:=\:\mathrm{1}.\mathrm{5}\:\mathrm{A} \\ $$$$\mathrm{V}_{\mathrm{p}} =\mathrm{V}_{\mathrm{1}} =\mathrm{V}_{\mathrm{2}} =\mathrm{3}\:\mathrm{Volt}\:\rightarrow\mathrm{ini}\:\mathrm{Sifat} \\ $$$$\mathrm{I}_{\mathrm{1}} \:=\frac{\mathrm{V}_{\mathrm{1}} }{\mathrm{R}_{\mathrm{1}} }\:=\frac{\mathrm{3}}{\mathrm{6}}\:=\mathrm{0}.\mathrm{5}\:\mathrm{A} \\ $$$$\mathrm{I}_{\mathrm{2}} =\frac{\mathrm{V}_{\mathrm{2}} }{\mathrm{R}_{\mathrm{2}} }\:=\frac{\mathrm{3}}{\mathrm{3}}\:=\:\mathrm{1}\:\mathrm{A} \\ $$$$\mathrm{Terbukti}= \\ $$$$\mathrm{I}_{\mathrm{p}} =\mathrm{I}_{\mathrm{1}} +\mathrm{I}_{\mathrm{2}} \\ $$$$\mathrm{1}.\mathrm{5}=\mathrm{0}.\mathrm{5}+\mathrm{1} \\ $$$$\mathrm{1}.\mathrm{5}=\mathrm{1}.\mathrm{5}\:\:\:\:\mathrm{terbukti} \\ $$
Commented by lyubita last updated on 06/Aug/21
$${crazy} \\ $$$${ask}\:{yourself}\:{answer}\:{yourself} \\ $$$$ \\ $$
Commented by yeti123 last updated on 10/Aug/21
$$\mathrm{idiot}!!! \\ $$