Question Number 150656 by mnjuly1970 last updated on 14/Aug/21
Answered by Ar Brandon last updated on 14/Aug/21
$$\Omega=\frac{\mathrm{1}}{\mathrm{2}}\left(\Gamma\left(\frac{\mathrm{1}}{\mathrm{2}}\right)+\Gamma\left(\mathrm{1}\right)+\Gamma\left(\frac{\mathrm{3}}{\mathrm{2}}\right)\right) \\ $$$$\:\:\:\:=\frac{\mathrm{1}}{\mathrm{2}}\left(\sqrt{\pi}+\mathrm{1}+\frac{\sqrt{\pi}}{\mathrm{2}}\right)=\frac{\mathrm{1}}{\mathrm{4}}\left(\mathrm{3}\sqrt{\pi}+\mathrm{2}\right) \\ $$
Commented by mnjuly1970 last updated on 14/Aug/21
$${mercey}.. \\ $$