Question Number 150801 by puissant last updated on 15/Aug/21
Commented by puissant last updated on 15/Aug/21
$${find}\:{tan}\theta\:{please}.. \\ $$
Commented by mr W last updated on 15/Aug/21
$$\theta\:{is}\:{undetermined}\:{with}\:{given}\: \\ $$$${condition}! \\ $$
Commented by puissant last updated on 15/Aug/21
$$\mathrm{2}{DE}=\mathrm{3}{EC} \\ $$
Commented by mr W last updated on 15/Aug/21
$$\theta=\mathrm{tan}^{−\mathrm{1}} \frac{\mathrm{3}}{\mathrm{5}}+\mathrm{tan}^{−\mathrm{1}} \frac{\mathrm{2}}{\mathrm{5}} \\ $$$$\mathrm{tan}\:\theta=\frac{\frac{\mathrm{3}}{\mathrm{5}}+\frac{\mathrm{2}}{\mathrm{5}}}{\mathrm{1}−\frac{\mathrm{3}}{\mathrm{5}}×\frac{\mathrm{2}}{\mathrm{5}}}=\frac{\mathrm{25}}{\mathrm{19}} \\ $$
Commented by puissant last updated on 15/Aug/21
$${nice}\:{sir}..\:{thank}\:{you}.. \\ $$