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Question-151444




Question Number 151444 by liberty last updated on 21/Aug/21
Answered by mr W last updated on 21/Aug/21
say BE=diameter=2×AB  ((BC)/(BO))=((BO)/(BE))  ⇒BC×BE=BO^2   ⇒BC×2×AB=BO^2   ⇒[ABCD]=BC×AB=((BO^2 )/2)=((10^2 )/2)=50
$${say}\:{BE}={diameter}=\mathrm{2}×{AB} \\ $$$$\frac{{BC}}{{BO}}=\frac{{BO}}{{BE}} \\ $$$$\Rightarrow{BC}×{BE}={BO}^{\mathrm{2}} \\ $$$$\Rightarrow{BC}×\mathrm{2}×{AB}={BO}^{\mathrm{2}} \\ $$$$\Rightarrow\left[{ABCD}\right]={BC}×{AB}=\frac{{BO}^{\mathrm{2}} }{\mathrm{2}}=\frac{\mathrm{10}^{\mathrm{2}} }{\mathrm{2}}=\mathrm{50} \\ $$
Commented by mr W last updated on 21/Aug/21
Commented by Tawa11 last updated on 21/Aug/21
Weldone sir.
$$\mathrm{Weldone}\:\mathrm{sir}. \\ $$
Answered by liberty last updated on 21/Aug/21

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