Question Number 152376 by fotosy2k last updated on 27/Aug/21
Commented by fotosy2k last updated on 28/Aug/21
$${pls}\:{help} \\ $$
Answered by imjagoll last updated on 28/Aug/21
$$\:\underset{\mathrm{n}\rightarrow\infty} {\mathrm{lim}}\:\frac{\mathrm{a}\left(\frac{\mathrm{a}}{\mathrm{b}}\right)^{\mathrm{n}} +\mathrm{b}}{\left(\frac{\mathrm{a}}{\mathrm{b}}\right)^{\mathrm{n}} +\mathrm{1}}\:=\:\mathrm{b}\: \\ $$$$\:\mathrm{note}\::\:\underset{\mathrm{n}\rightarrow\infty} {\mathrm{lim}}\left(\frac{\mathrm{a}}{\mathrm{b}}\right)^{\mathrm{n}} =\mathrm{0}\:,\:\mathrm{a}<\mathrm{b} \\ $$