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Question-152682




Question Number 152682 by alcohol last updated on 31/Aug/21
Answered by Olaf_Thorendsen last updated on 31/Aug/21
Time taken 1 second.  Potential energy E_P  :  E_P  = mgh = 50×9,81×40 = 19620 J  Kinetic energy E_K  :  E_K  = (1/2)mv^2  = (1/2)×50×8^2  = 1600 J  Now, the work done per second is :  P_u  = ((19620J+1600J)/(1s)) = 21220W
Timetaken1second.PotentialenergyEP:EP=mgh=50×9,81×40=19620JKineticenergyEK:EK=12mv2=12×50×82=1600JNow,theworkdonepersecondis:Pu=19620J+1600J1s=21220W

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