Question Number 152723 by Tawa11 last updated on 31/Aug/21
Answered by Olaf_Thorendsen last updated on 31/Aug/21
$$\mathrm{V}_{\mathrm{5}\Omega} \:=\:\mathrm{5}\Omega×\mathrm{I}_{\mathrm{5}\Omega} \:=\:\mathrm{5}\Omega×\mathrm{2A}\:=\:\mathrm{10V} \\ $$$$\mathrm{V}_{\mathrm{10}\Omega} \:=\:\mathrm{V}_{\mathrm{5}\Omega} \:=\:\mathrm{10V} \\ $$$$\mathrm{I}_{\mathrm{10}\Omega} \:=\:\frac{\mathrm{V}_{\mathrm{10}\Omega} }{\mathrm{10}\Omega}\:=\:\frac{\mathrm{10V}}{\mathrm{10}\Omega}\:=\:\mathrm{1A} \\ $$$$\mathrm{I}_{\mathrm{20}\Omega} \:=\:\mathrm{I}_{\mathrm{5}\Omega} +\mathrm{I}_{\mathrm{10}\Omega} \:=\:\mathrm{2A}+\mathrm{1A}\:=\:\mathrm{3A} \\ $$$$\mathrm{V}_{\mathrm{20}\Omega} \:=\:\mathrm{20}\Omega×\mathrm{I}_{\mathrm{20}\Omega} \:=\:\mathrm{20}\Omega×\mathrm{3A}\:=\:\mathrm{60V} \\ $$
Commented by Tawa11 last updated on 31/Aug/21
$$\mathrm{Wow},\:\mathrm{thanks}\:\mathrm{sir}.\:\mathrm{I}\:\mathrm{appreciate}.\:\mathrm{God}\:\mathrm{bless}\:\mathrm{you}. \\ $$