Question-152740 Tinku Tara June 4, 2023 Geometry 0 Comments FacebookTweetPin Question Number 152740 by mr W last updated on 31/Aug/21 Commented by mr W last updated on 31/Aug/21 [Q152712] Answered by mr W last updated on 31/Aug/21 Commented by mr W last updated on 31/Aug/21 AF=CLEO=CL2LM=23×EO=CL3CM=23×CL⇒CLCM=32GF=CN2MN=AG3⇒AG=3×MNAG+GF=AF=CL3×MN+CN2=CL…(i)MN+CN=23×CL…(ii)3×(ii)−(i):52×CN=CL⇒CLCN=52CLCL+CLCM=1+32=52=CLCN⇒1CL+1CM=1CN Commented by Tawa11 last updated on 31/Aug/21 Godblessyousir.Iappreciatesir. Terms of Service Privacy Policy Contact: info@tinkutara.com FacebookTweetPin Post navigation Previous Previous post: Question-21661Next Next post: 0-cos-2cos-x-1-1-3-2-ln-x-4-1-x-4-dx- Leave a Reply Cancel replyYour email address will not be published. Required fields are marked *Comment * Name * Save my name, email, and website in this browser for the next time I comment.