Question-152748

Question Number 152748 by Tawa11 last updated on 01/Sep/21

Answered by Olaf_Thorendsen last updated on 01/Sep/21

R_{T} : total resistance

E = R_{T} I = \frac{I}{\frac{1}{R} + \frac{1}{X}} = \frac{3 A}{\frac{1}{5 Ω} + \frac{1}{X}} = \frac{6 A}{\frac{1}{2 Ω} + \frac{1}{X}}

3 (\frac{1}{2} + \frac{1}{X}) = 6 (\frac{1}{5} + \frac{1}{X})

1, 5 + \frac{3}{X} = 1, 2 + \frac{6}{X}

\frac{3}{X} = 1, 5 - 1, 2 = 0, 3

X = 10 Ω (Answer C)

Commented by Tawa11 last updated on 01/Sep/21

Thanks for your time sir . God bless you . I appreciate .

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