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Question-152805




Question Number 152805 by mathlove last updated on 01/Sep/21
Answered by MJS_new last updated on 01/Sep/21
x≥0  3ln 2 x=7ln 2 (√x)  3x=7(√x)  x=0∨x=((49)/9)
$${x}\geqslant\mathrm{0} \\ $$$$\mathrm{3ln}\:\mathrm{2}\:{x}=\mathrm{7ln}\:\mathrm{2}\:\sqrt{{x}} \\ $$$$\mathrm{3}{x}=\mathrm{7}\sqrt{{x}} \\ $$$${x}=\mathrm{0}\vee{x}=\frac{\mathrm{49}}{\mathrm{9}} \\ $$
Answered by JDamian last updated on 01/Sep/21
2^(3x) =2^(7(√x))   3x=7(√x)  9x^2 −49x=0  ⇒  { ((x=0)),((9x−49=0  ⇒ x=((49)/9)=((7/3))^2 )) :}
$$\mathrm{2}^{\mathrm{3}{x}} =\mathrm{2}^{\mathrm{7}\sqrt{{x}}} \\ $$$$\mathrm{3}{x}=\mathrm{7}\sqrt{{x}} \\ $$$$\mathrm{9}{x}^{\mathrm{2}} −\mathrm{49}{x}=\mathrm{0}\:\:\Rightarrow\:\begin{cases}{{x}=\mathrm{0}}\\{\mathrm{9}{x}−\mathrm{49}=\mathrm{0}\:\:\Rightarrow\:{x}=\frac{\mathrm{49}}{\mathrm{9}}=\left(\frac{\mathrm{7}}{\mathrm{3}}\right)^{\mathrm{2}} }\end{cases}\: \\ $$
Commented by otchereabdullai@gmail.com last updated on 08/Sep/21
nice one!
$$\mathrm{nice}\:\mathrm{one}! \\ $$

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