Question-152912

Question Number 152912 by mathdanisur last updated on 03/Sep/21

Answered by ghimisi last updated on 03/Sep/21

Σ \frac{a}{2 b + 3 c} = Σ \frac{a^{2}}{2 a b + 3 a c} ⩾ \frac{{(a + b + c)}^{2}}{5 (a b + b c + a c)} ⩾ \frac{3 (a b + b c + c a)}{5 (a b + b c + a c)} = \frac{3}{5}

Commented by ghimisi last updated on 03/Sep/21

Σ \frac{a}{3 b + 2 c} = Σ \frac{a^{2}}{3 a b + 2 a c} ⩾ \frac{{(a + b + c)}^{2}}{5 (a b + b c + a c)} ⩾ \frac{3 (a b + b c + c a)}{5 (a b + b c + a c)} = \frac{3}{5}

Commented by mathdanisur last updated on 03/Sep/21

Nice S er thank you