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Question-153447




Question Number 153447 by rexford last updated on 07/Sep/21
Commented by rexford last updated on 07/Sep/21
please,i need help on this seriously
$${please},{i}\:{need}\:{help}\:{on}\:{this}\:{seriously} \\ $$
Answered by Jonathanwaweh last updated on 07/Sep/21
y=3x⇒var(y)=var(3x)             ⇒var(y)=3^2 var(x)             ⇒var(y)=3^2 ×4=36
$${y}=\mathrm{3}{x}\Rightarrow{var}\left({y}\right)={var}\left(\mathrm{3}{x}\right) \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\Rightarrow{var}\left({y}\right)=\mathrm{3}^{\mathrm{2}} {var}\left({x}\right) \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\Rightarrow{var}\left({y}\right)=\mathrm{3}^{\mathrm{2}} ×\mathrm{4}=\mathrm{36} \\ $$
Answered by prakash jain last updated on 07/Sep/21
Variance(aX+b)=a^2 Variance(X)  a=3  b=9  Variamce(Y)=9^2 ×4=36
$${Variance}\left({aX}+{b}\right)={a}^{\mathrm{2}} {Variance}\left({X}\right) \\ $$$${a}=\mathrm{3} \\ $$$${b}=\mathrm{9} \\ $$$${Variamce}\left({Y}\right)=\mathrm{9}^{\mathrm{2}} ×\mathrm{4}=\mathrm{36} \\ $$

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