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Question-154396




Question Number 154396 by DELETED last updated on 18/Sep/21
Answered by DELETED last updated on 18/Sep/21
f(x)=(1/3)x^3 −500x^2 +6000.000  (dy/dx)=x^2 −1000x  syarat maximum , (dy/dx)=0  x^2 −1000x=0  x(x−1000)=0  x_1 =0 dan x_2 =1000
$$\mathrm{f}\left(\mathrm{x}\right)=\frac{\mathrm{1}}{\mathrm{3}}\mathrm{x}^{\mathrm{3}} −\mathrm{500x}^{\mathrm{2}} +\mathrm{6000}.\mathrm{000} \\ $$$$\frac{\mathrm{dy}}{\mathrm{dx}}=\mathrm{x}^{\mathrm{2}} −\mathrm{1000x} \\ $$$$\mathrm{syarat}\:\mathrm{maximum}\:,\:\frac{\mathrm{dy}}{\mathrm{dx}}=\mathrm{0} \\ $$$$\mathrm{x}^{\mathrm{2}} −\mathrm{1000x}=\mathrm{0} \\ $$$$\mathrm{x}\left(\mathrm{x}−\mathrm{1000}\right)=\mathrm{0} \\ $$$$\mathrm{x}_{\mathrm{1}} =\mathrm{0}\:\mathrm{dan}\:\mathrm{x}_{\mathrm{2}} =\mathrm{1000} \\ $$

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