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Question-154398




Question Number 154398 by DELETED last updated on 18/Sep/21
Answered by DELETED last updated on 18/Sep/21
2).  ^6 P_3  = ((6!)/((6−3)!)) = ((6!)/(3!)) =((6×5×4×3!)/(3!))            =6×5×4       yg >400 ada: 3×5×4=60 buah   Jawaban: B
$$\left.\mathrm{2}\right).\:\overset{\mathrm{6}} {\:}\mathrm{P}_{\mathrm{3}} \:=\:\frac{\mathrm{6}!}{\left(\mathrm{6}−\mathrm{3}\right)!}\:=\:\frac{\mathrm{6}!}{\mathrm{3}!}\:=\frac{\mathrm{6}×\mathrm{5}×\mathrm{4}×\mathrm{3}!}{\mathrm{3}!} \\ $$$$\:\:\:\:\:\:\:\:\:\:=\mathrm{6}×\mathrm{5}×\mathrm{4} \\ $$$$\:\:\:\:\:\mathrm{yg}\:>\mathrm{400}\:\mathrm{ada}:\:\mathrm{3}×\mathrm{5}×\mathrm{4}=\mathrm{60}\:\mathrm{buah} \\ $$$$\:\mathrm{Jawaban}:\:\mathrm{B} \\ $$

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