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Question-154777




Question Number 154777 by Khalmohmmad last updated on 21/Sep/21
Answered by john_santu last updated on 21/Sep/21
it should be lim_(k→5) (((k^2 −25)/(k−5)))=k+5  or if lim_(x→5) (((k^2 −25)/(k−5)))=(((k^2 −25)/(k−5)))×lim_(x→5) (1)  = ((k^2 −25)/(k−5))=k+5
$${it}\:{should}\:{be}\:\underset{{k}\rightarrow\mathrm{5}} {\mathrm{lim}}\left(\frac{{k}^{\mathrm{2}} −\mathrm{25}}{{k}−\mathrm{5}}\right)={k}+\mathrm{5} \\ $$$${or}\:{if}\:\underset{{x}\rightarrow\mathrm{5}} {\mathrm{lim}}\left(\frac{{k}^{\mathrm{2}} −\mathrm{25}}{{k}−\mathrm{5}}\right)=\left(\frac{{k}^{\mathrm{2}} −\mathrm{25}}{{k}−\mathrm{5}}\right)×\underset{{x}\rightarrow\mathrm{5}} {\mathrm{lim}}\left(\mathrm{1}\right) \\ $$$$=\:\frac{{k}^{\mathrm{2}} −\mathrm{25}}{{k}−\mathrm{5}}={k}+\mathrm{5} \\ $$

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