Question-155035 Tinku Tara June 4, 2023 Mechanics 0 Comments FacebookTweetPin Question Number 155035 by peter frank last updated on 24/Sep/21 Answered by mr W last updated on 24/Sep/21 hmax=u02sin2θ2gp.e.ath=hmax2=u02sin2θ4gism0gh=m0u02sin2θ4 Commented by peter frank last updated on 25/Sep/21 thankyou Terms of Service Privacy Policy Contact: info@tinkutara.com FacebookTweetPin Post navigation Previous Previous post: Question-89496Next Next post: Question-155033 Leave a Reply Cancel replyYour email address will not be published. Required fields are marked *Comment * Name * Save my name, email, and website in this browser for the next time I comment.