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Question-155035




Question Number 155035 by peter frank last updated on 24/Sep/21
Answered by mr W last updated on 24/Sep/21
h_(max) =((u_0 ^2 sin^2  θ)/(2g))  p.e. at h=(h_(max) /2)=((u_0 ^2 sin^2  θ)/(4g)) is  m_0 gh=((m_0 u_0 ^2 sin^2  θ)/4)
hmax=u02sin2θ2gp.e.ath=hmax2=u02sin2θ4gism0gh=m0u02sin2θ4
Commented by peter frank last updated on 25/Sep/21
thank you
thankyou

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