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Question-155122




Question Number 155122 by saly last updated on 25/Sep/21
Commented by benhamimed last updated on 25/Sep/21
/x−3/+3−x≠0  /x−3/= { ((x−3   ;x≥3)),((3−x    ;x≤3)) :}  /x−3/+3−x= { ((0   ;x≥3)),((6−2x   ;x≤0)) :}  D=]−∞;3[
/x3/+3x0/x3/={x3;x33x;x3/x3/+3x={0;x362x;x0D=];3[
Commented by saly last updated on 25/Sep/21
  thank you
thankyou

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