Question-155294

Question Number 155294 by peter frank last updated on 28/Sep/21

Answered by peter frank last updated on 30/Sep/21

Commented by peter frank last updated on 30/Sep/21

Point P = point B

R_{1} = \frac{v_{o}^{2} \sin 2 θ_{1}}{g} = 0 . 899 m θ_{1} = 46

R_{2} = \frac{v_{o}^{2} \sin 2 θ_{2}}{g} = 0 . 899 m θ_{2} = 44

R_{1} = R_{2} hencd both particle

focused on the same point P

(b) h = h_{2} - h_{1}

h_{2} = \frac{v_{o}^{2} \sin^{2} θ_{2}}{2 g}

h_{1} = \frac{v_{o}^{2} \sin^{2} θ_{1}}{2 g}

g = a = 4 \times 10^{13} m / s^{2}

hence

h = 0 . 233 m