Question Number 155426 by ajfour last updated on 30/Sep/21
Commented by talminator2856791 last updated on 30/Sep/21
$$\: \\ $$$$\:\:\mathrm{30}:\mathrm{60}:\mathrm{90}\: \\ $$$$\:\Rightarrow\:{OE}\:=\:\sqrt{\mathrm{3}} \\ $$$$\: \\ $$
Commented by otchereabdullai@gmail.com last updated on 08/Oct/21
$$\mathrm{nice}! \\ $$
Answered by Rasheed.Sindhi last updated on 30/Sep/21
$$\angle\mathrm{AOE}=\mathrm{30} \\ $$$$\therefore\:\mathrm{OA}=\mathrm{2AE}=\mathrm{2}\left(\mathrm{1}\right)=\mathrm{2} \\ $$$$\mathrm{AE}=\sqrt{\left(\mathrm{OA}\right)^{\mathrm{2}} −\left(\mathrm{AE}\right)^{\mathrm{2}} } \\ $$$$\:\:\:\mathrm{x}=\sqrt{\mathrm{2}^{\mathrm{2}} −\mathrm{1}^{\mathrm{2}} }\:=\sqrt{\mathrm{3}} \\ $$
Commented by ajfour last updated on 30/Sep/21
$${x}^{\mathrm{3}} −{x}={c} \\ $$