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Question-155497




Question Number 155497 by VIDDD last updated on 01/Oct/21
Answered by amin96 last updated on 01/Oct/21
(√(4−(1/(3(√2)))(√(4−(1/(3(√2)))…))))=x    (√(4−(1/(3(√2)))x))=x   ⇒   x^2 =4−(x/(3(√2)))  ⇒  3x^2 (√2)+x−12(√2)=0  𝚫=289     x=((−1+17)/(6(√2)))=(8/(3(√2)))  A=10+log_(3/2) ((1/(3(√2)))×(8/(3(√2))))=10+log_(3/2) (4/9)=  =10+2log_(3/2) (2/3)  =10+2log_(3/2) ((3/2))^(−1) =10−2=8
41324132=x4132x=xx2=4x323x22+x122=0Δ=289x=1+1762=832A=10+log32(132×832)=10+log3249==10+2log3223=10+2log32(32)1=102=8
Commented by puissant last updated on 01/Oct/21
Nice Sir really great...
NiceSirreallygreat
Commented by VIDDD last updated on 01/Oct/21
great sir ,thanks
greatsir,thanks

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