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Question-155531




Question Number 155531 by mathdanisur last updated on 01/Oct/21
Commented by ghimisi last updated on 02/Oct/21
min=−(1/4)      (a=(1/4);b=(1/2);c=(1/4))
$${min}=−\frac{\mathrm{1}}{\mathrm{4}}\:\:\:\:\:\:\left({a}=\frac{\mathrm{1}}{\mathrm{4}};{b}=\frac{\mathrm{1}}{\mathrm{2}};{c}=\frac{\mathrm{1}}{\mathrm{4}}\right) \\ $$
Commented by mathdanisur last updated on 02/Oct/21
Thank you Ser, can you tell me how  this part was obtained, please if possible
$$\mathrm{Thank}\:\mathrm{you}\:\boldsymbol{\mathrm{S}}\mathrm{er},\:\mathrm{can}\:\mathrm{you}\:\mathrm{tell}\:\mathrm{me}\:\mathrm{how} \\ $$$$\mathrm{this}\:\mathrm{part}\:\mathrm{was}\:\mathrm{obtained},\:\mathrm{please}\:\mathrm{if}\:\mathrm{possible} \\ $$
Commented by ghimisi last updated on 02/Oct/21
c=1−a−b  minimul functiei de gradul 2
$${c}=\mathrm{1}−{a}−{b} \\ $$$${minimul}\:{functiei}\:{de}\:{gradul}\:\mathrm{2} \\ $$$$ \\ $$
Commented by mathdanisur last updated on 02/Oct/21
Thank you Ser, very nice
$$\mathrm{Thank}\:\mathrm{you}\:\boldsymbol{\mathrm{S}}\mathrm{er},\:\mathrm{very}\:\mathrm{nice} \\ $$

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