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Question-155583




Question Number 155583 by cortano last updated on 02/Oct/21
Answered by yeti123 last updated on 02/Oct/21
x = 6.4172604685892...  x ≈ 6.417260
$${x}\:=\:\mathrm{6}.\mathrm{4172604685892}… \\ $$$${x}\:\approx\:\mathrm{6}.\mathrm{417260} \\ $$
Answered by peter frank last updated on 02/Oct/21
x−5log (5x−2)=2x+1log (x−5)  (((x−5)/(2x+1)))log (5x−2)−log (x−5)=0  ....
$$\mathrm{x}−\mathrm{5log}\:\left(\mathrm{5x}−\mathrm{2}\right)=\mathrm{2x}+\mathrm{1log}\:\left(\mathrm{x}−\mathrm{5}\right) \\ $$$$\left(\frac{\mathrm{x}−\mathrm{5}}{\mathrm{2x}+\mathrm{1}}\right)\mathrm{log}\:\left(\mathrm{5x}−\mathrm{2}\right)−\mathrm{log}\:\left(\mathrm{x}−\mathrm{5}\right)=\mathrm{0} \\ $$$$…. \\ $$$$ \\ $$

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