Menu Close

Question-155735




Question Number 155735 by BHOOPENDRA last updated on 04/Oct/21
Answered by ajfour last updated on 04/Oct/21
Commented by ajfour last updated on 04/Oct/21
x^2 +(y−(1/2))^2 =1^2 +((1/2))^2   ⇒ x^2 +y^2 −y−1=0
$${x}^{\mathrm{2}} +\left({y}−\frac{\mathrm{1}}{\mathrm{2}}\right)^{\mathrm{2}} =\mathrm{1}^{\mathrm{2}} +\left(\frac{\mathrm{1}}{\mathrm{2}}\right)^{\mathrm{2}} \\ $$$$\Rightarrow\:{x}^{\mathrm{2}} +{y}^{\mathrm{2}} −{y}−\mathrm{1}=\mathrm{0} \\ $$
Commented by BHOOPENDRA last updated on 04/Oct/21
nice sir
$${nice}\:{sir} \\ $$
Commented by BHOOPENDRA last updated on 04/Oct/21
which option is correct ?
$${which}\:{option}\:{is}\:{correct}\:? \\ $$

Leave a Reply

Your email address will not be published. Required fields are marked *