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Question-155978




Question Number 155978 by mnjuly1970 last updated on 06/Oct/21
Commented by mr W last updated on 06/Oct/21
i think for any a the eqn. has always  solution.
$${i}\:{think}\:{for}\:{any}\:{a}\:{the}\:{eqn}.\:{has}\:{always} \\ $$$${solution}. \\ $$
Commented by mr W last updated on 07/Oct/21
i thought about the question again.  i think ⌊2x⌋+⌊x⌋=2 has no solution,  therefore  a^2 −a≠2  a^2 −a−2≠0  (a−2)(a+1)≠0  a≠2, a≠−1  is this the correct answer sir?
$${i}\:{thought}\:{about}\:{the}\:{question}\:{again}. \\ $$$${i}\:{think}\:\lfloor\mathrm{2}{x}\rfloor+\lfloor{x}\rfloor=\mathrm{2}\:{has}\:{no}\:{solution}, \\ $$$${therefore} \\ $$$${a}^{\mathrm{2}} −{a}\neq\mathrm{2} \\ $$$${a}^{\mathrm{2}} −{a}−\mathrm{2}\neq\mathrm{0} \\ $$$$\left({a}−\mathrm{2}\right)\left({a}+\mathrm{1}\right)\neq\mathrm{0} \\ $$$${a}\neq\mathrm{2},\:{a}\neq−\mathrm{1} \\ $$$${is}\:{this}\:{the}\:{correct}\:{answer}\:{sir}? \\ $$

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