Question Number 155996 by horpy4 last updated on 07/Oct/21
Answered by yeti123 last updated on 07/Oct/21
$$\mathrm{using}\:\mathrm{formula}: \\ $$$${K}_{{p}} \:=\:{K}_{{c}} \left({RT}\right)^{\Delta{n}} \\ $$$${K}_{{c}} \:=\:{K}_{{p}} \left({RT}\right)^{−\Delta{n}} \\ $$$$\:\:\:\:\:\:\:=\:\mathrm{1}.\mathrm{3}×\mathrm{10}^{\mathrm{4}} \left(\mathrm{0}.\mathrm{082057}\:\mathrm{L}\centerdot\mathrm{atm}/\mathrm{mol}\centerdot\mathrm{K}×\mathrm{457}\:\mathrm{K}\right)^{−\left(\mathrm{2}−\mathrm{3}\right)} \\ $$$$\:\:\:\:\:\:\:=\:… \\ $$