Menu Close

Question-156093




Question Number 156093 by otchereabdullai@gmail.com last updated on 07/Oct/21
Answered by otchereabdullai@gmail.com last updated on 07/Oct/21
Commented by otchereabdullai@gmail.com last updated on 07/Oct/21
please i looked at it this way please   check for me if is correct
$$\mathrm{please}\:\mathrm{i}\:\mathrm{looked}\:\mathrm{at}\:\mathrm{it}\:\mathrm{this}\:\mathrm{way}\:\mathrm{please}\: \\ $$$$\mathrm{check}\:\mathrm{for}\:\mathrm{me}\:\mathrm{if}\:\mathrm{is}\:\mathrm{correct} \\ $$
Answered by mr W last updated on 08/Oct/21
Commented by otchereabdullai@gmail.com last updated on 07/Oct/21
God richly bless you prof W  Am much grateful to you all the time
$$\mathrm{God}\:\mathrm{richly}\:\mathrm{bless}\:\mathrm{you}\:\mathrm{prof}\:\mathrm{W} \\ $$$$\mathrm{Am}\:\mathrm{much}\:\mathrm{grateful}\:\mathrm{to}\:\mathrm{you}\:\mathrm{all}\:\mathrm{the}\:\mathrm{time} \\ $$
Commented by mr W last updated on 07/Oct/21
∠ADC+∠ABC=180°  ⇒∠ADC=180°−158°=22°  ∠ADE+∠ADC=90°  ⇒∠ADE=90°−22°=68°  ∠ABE=∠ADE=68°
$$\angle{ADC}+\angle{ABC}=\mathrm{180}° \\ $$$$\Rightarrow\angle{ADC}=\mathrm{180}°−\mathrm{158}°=\mathrm{22}° \\ $$$$\angle{ADE}+\angle{ADC}=\mathrm{90}° \\ $$$$\Rightarrow\angle{ADE}=\mathrm{90}°−\mathrm{22}°=\mathrm{68}° \\ $$$$\angle{ABE}=\angle{ADE}=\mathrm{68}° \\ $$
Commented by mr W last updated on 07/Oct/21
or  ∠EBC=90°  ⇒∠ABE=158°−90°=68°  ∠ADE=∠ABE=68°
$${or} \\ $$$$\angle{EBC}=\mathrm{90}° \\ $$$$\Rightarrow\angle{ABE}=\mathrm{158}°−\mathrm{90}°=\mathrm{68}° \\ $$$$\angle{ADE}=\angle{ABE}=\mathrm{68}° \\ $$
Commented by Tawa11 last updated on 08/Oct/21
great sir
$$\mathrm{great}\:\mathrm{sir} \\ $$

Leave a Reply

Your email address will not be published. Required fields are marked *