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Question-156534




Question Number 156534 by otchereabdullai@gmail.com last updated on 12/Oct/21
Commented by otchereabdullai@gmail.com last updated on 12/Oct/21
please help me with these question
$$\mathrm{please}\:\mathrm{help}\:\mathrm{me}\:\mathrm{with}\:\mathrm{these}\:\mathrm{question} \\ $$
Answered by puissant last updated on 12/Oct/21
b)  A = A_1 +A_2 +A_3   A_1 =(((G_b +P_b )×h)/2)=(((8+6)×4)/2)=28..  A_2 =(((8+2)×2)/2)=10  A_3 =C×C=2×2=4..  ⇒  A = 28+10+4 = 42 cm^2 ....   ⇒ A = 42 cm^2 ..
$$\left.{b}\right) \\ $$$$\mathscr{A}\:=\:\mathscr{A}_{\mathrm{1}} +\mathscr{A}_{\mathrm{2}} +\mathscr{A}_{\mathrm{3}} \\ $$$$\mathscr{A}_{\mathrm{1}} =\frac{\left({G}_{{b}} +{P}_{{b}} \right)×{h}}{\mathrm{2}}=\frac{\left(\mathrm{8}+\mathrm{6}\right)×\mathrm{4}}{\mathrm{2}}=\mathrm{28}.. \\ $$$$\mathscr{A}_{\mathrm{2}} =\frac{\left(\mathrm{8}+\mathrm{2}\right)×\mathrm{2}}{\mathrm{2}}=\mathrm{10} \\ $$$$\mathscr{A}_{\mathrm{3}} ={C}×{C}=\mathrm{2}×\mathrm{2}=\mathrm{4}.. \\ $$$$\Rightarrow\:\:\mathscr{A}\:=\:\mathrm{28}+\mathrm{10}+\mathrm{4}\:=\:\mathrm{42}\:{cm}^{\mathrm{2}} ….\: \\ $$$$\Rightarrow\:\mathscr{A}\:=\:\mathrm{42}\:{cm}^{\mathrm{2}} .. \\ $$
Commented by otchereabdullai@gmail.com last updated on 12/Oct/21
God richly bless you sir! am much   much grateful for your time !
$$\mathrm{God}\:\mathrm{richly}\:\mathrm{bless}\:\mathrm{you}\:\mathrm{sir}!\:\mathrm{am}\:\mathrm{much}\: \\ $$$$\mathrm{much}\:\mathrm{grateful}\:\mathrm{for}\:\mathrm{your}\:\mathrm{time}\:! \\ $$
Commented by otchereabdullai@gmail.com last updated on 12/Oct/21
Can you please define the terms for   me G_(b ) , P_b
$$\mathrm{Can}\:\mathrm{you}\:\mathrm{please}\:\mathrm{define}\:\mathrm{the}\:\mathrm{terms}\:\mathrm{for}\: \\ $$$$\mathrm{me}\:\mathrm{G}_{\mathrm{b}\:} ,\:\mathrm{P}_{\mathrm{b}} \\ $$
Commented by puissant last updated on 13/Oct/21
G_b =large base  and  P_b =small base..
$${G}_{{b}} ={large}\:{base}\:\:{and}\:\:{P}_{{b}} ={small}\:{base}.. \\ $$
Commented by otchereabdullai@gmail.com last updated on 13/Oct/21
well understood sir! God bless you
$$\mathrm{well}\:\mathrm{understood}\:\mathrm{sir}!\:\mathrm{God}\:\mathrm{bless}\:\mathrm{you} \\ $$
Answered by puissant last updated on 12/Oct/21
c)  A = 48−(9+8+6+4) = 48−27 = 21  ⇒ A = 21 cm^2 ..
$$\left.{c}\right) \\ $$$$\mathscr{A}\:=\:\mathrm{48}−\left(\mathrm{9}+\mathrm{8}+\mathrm{6}+\mathrm{4}\right)\:=\:\mathrm{48}−\mathrm{27}\:=\:\mathrm{21} \\ $$$$\Rightarrow\:\mathscr{A}\:=\:\mathrm{21}\:{cm}^{\mathrm{2}} .. \\ $$
Commented by otchereabdullai@gmail.com last updated on 12/Oct/21
well understood thanks soo much!
$$\mathrm{well}\:\mathrm{understood}\:\mathrm{thanks}\:\mathrm{soo}\:\mathrm{much}! \\ $$

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