Question Number 156640 by semanou last updated on 13/Oct/21
Answered by puissant last updated on 13/Oct/21
$$\left.{c}\right) \\ $$$$\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\frac{{x}}{{tanx}}=\:\mathrm{1} \\ $$$$\left.{d}\right) \\ $$$$\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\frac{{x}}{{sinx}}=\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\frac{\mathrm{1}}{\frac{{sinx}}{{x}}}=\frac{\mathrm{1}}{\mathrm{1}}=\mathrm{1}.. \\ $$$$\left.{e}\right) \\ $$$$\underset{{x}\rightarrow+\infty} {\mathrm{lim}}\:\frac{\mathrm{1}}{\:\sqrt{{x}}}\:=\:\mathrm{0}\:.. \\ $$