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Question-156710




Question Number 156710 by cortano last updated on 14/Oct/21
Commented by mr W last updated on 14/Oct/21
question is wrong. no unique solution!  you can make any length AD>3.
$${question}\:{is}\:{wrong}.\:{no}\:{unique}\:{solution}! \\ $$$${you}\:{can}\:{make}\:{any}\:{length}\:{AD}>\mathrm{3}. \\ $$
Commented by mr W last updated on 14/Oct/21
Commented by mr W last updated on 14/Oct/21
i think correct question could be  yellow=gray=^(area) blue=red=^(area) black
$${i}\:{think}\:{correct}\:{question}\:{could}\:{be} \\ $$$${yellow}={gray}\overset{{area}} {=}{blue}={red}\overset{{area}} {=}{black} \\ $$
Commented by cortano last updated on 15/Oct/21
thank you all
$$\mathrm{thank}\:\mathrm{you}\:\mathrm{all} \\ $$
Answered by Rasheed.Sindhi last updated on 14/Oct/21
AD=3+a , AB=2+b  ∀a,b∈R^+   Yellow=Gray=2a  Blue=Red=3b  ∴AD(>3) is not unique.
$${AD}=\mathrm{3}+{a}\:,\:{AB}=\mathrm{2}+{b} \\ $$$$\forall{a},{b}\in\mathbb{R}^{+} \\ $$$${Yellow}={Gray}=\mathrm{2}{a} \\ $$$${Blue}={Red}=\mathrm{3}{b} \\ $$$$\therefore{AD}\left(>\mathrm{3}\right)\:{is}\:{not}\:{unique}. \\ $$$$ \\ $$

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