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Question-156913




Question Number 156913 by cortano last updated on 17/Oct/21
Answered by mr W last updated on 17/Oct/21
Commented by cortano last updated on 17/Oct/21
blue length = 10 . yes thanks
bluelength=10.yesthanks
Commented by mr W last updated on 17/Oct/21
OD=(√((R−r)^2 −r^2 ))=(√(R(R−2r)))  FD=R+(√(R(R−2r)))=blue  OE=OD−r=(√(R(R−2r)))−r  EG=R−OE  FE=R+OE  AE^2 =FE×EG=R^2 −OE^2   FA^2 =AE^2 +FE^2 =R^2 −OE^2 +FE^2   FA^2 =R^2 −OE^2 +(R+OE)^2   FA^2 =2R^2 +2R×OE  FA^2 =2R^2 +2R×[(√(R(R−2r)))−r]  FA^2 =R^2 +2R(√(R(R−2r)))+R(R−2r)  FA^2 =[R+(√(R(R−2r)))]^2   FA=R+(√(R(R−2r)))=gree  it is to see FD=FA, i.e. blue=green.
OD=(Rr)2r2=R(R2r)FD=R+R(R2r)=blueOE=ODr=R(R2r)rEG=ROEFE=R+OEAE2=FE×EG=R2OE2FA2=AE2+FE2=R2OE2+FE2FA2=R2OE2+(R+OE)2FA2=2R2+2R×OEFA2=2R2+2R×[R(R2r)r]FA2=R2+2RR(R2r)+R(R2r)FA2=[R+R(R2r)]2FA=R+R(R2r)=greeitistoseeFD=FA,i.e.blue=green.
Commented by Tawa11 last updated on 17/Oct/21
great sir
greatsir

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