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Question-157531




Question Number 157531 by mathlove last updated on 24/Oct/21
Answered by phanphuoc last updated on 24/Oct/21
you can watch youtuber blackpenredpen
$${you}\:{can}\:{watch}\:{youtuber}\:{blackpenredpen} \\ $$$$ \\ $$
Answered by MJS_new last updated on 24/Oct/21
∫_(−a) ^a xdx=[(x^2 /2)]_(−a) ^a =((a^2 −a^2 )/2)=0  lim_(a→+∞) ((a^2 −a^2 )/2) =0
$$\underset{−{a}} {\overset{{a}} {\int}}{xdx}=\left[\frac{{x}^{\mathrm{2}} }{\mathrm{2}}\right]_{−{a}} ^{{a}} =\frac{{a}^{\mathrm{2}} −{a}^{\mathrm{2}} }{\mathrm{2}}=\mathrm{0} \\ $$$$\underset{{a}\rightarrow+\infty} {\mathrm{lim}}\frac{{a}^{\mathrm{2}} −{a}^{\mathrm{2}} }{\mathrm{2}}\:=\mathrm{0} \\ $$

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