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Question-158735




Question Number 158735 by Ashraful Islam last updated on 08/Nov/21
Commented by Ashraful Islam last updated on 08/Nov/21
hello , how is it infinity ? anyone can explain please .
Commented by mnjuly1970 last updated on 08/Nov/21
        lim_( h→0^( −) )  (( −2h +6)/h)=lim_( x→0^− ) ((−2h)/h)+lim_( h→0^− ) (6/h)     = −2 +(( 6)/0^− ) = −2+(−∞)=−∞
$$\:\:\: \\ $$$$\:\:\:{lim}_{\:{h}\rightarrow\mathrm{0}^{\:−} } \:\frac{\:−\mathrm{2}{h}\:+\mathrm{6}}{{h}}={lim}_{\:{x}\rightarrow\mathrm{0}^{−} } \frac{−\mathrm{2}{h}}{{h}}+{lim}_{\:{h}\rightarrow\mathrm{0}^{−} } \frac{\mathrm{6}}{{h}} \\ $$$$\:\:\:=\:−\mathrm{2}\:+\frac{\:\mathrm{6}}{\mathrm{0}^{−} }\:=\:−\mathrm{2}+\left(−\infty\right)=−\infty \\ $$

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