Question Number 159157 by physicstutes last updated on 13/Nov/21
Answered by mr W last updated on 13/Nov/21
Commented by mr W last updated on 13/Nov/21
$${let}\:{AA}'=\mathrm{1} \\ $$$$\Rightarrow{BB}'=\frac{\mathrm{50}}{\mathrm{450}}×\mathrm{1}=\frac{\mathrm{1}}{\mathrm{9}} \\ $$$$\Rightarrow{CC}'={BB}'=\frac{\mathrm{1}}{\mathrm{9}} \\ $$$$\Rightarrow{DD}'=\frac{\mathrm{75}}{\mathrm{300}+\mathrm{75}}×\frac{\mathrm{1}}{\mathrm{9}}=\frac{\mathrm{1}}{\mathrm{45}} \\ $$$${P}×\mathrm{1}=\mathrm{9}×\frac{\mathrm{1}}{\mathrm{45}} \\ $$$$\Rightarrow{P}=\frac{\mathrm{1}}{\mathrm{5}}\:{KN} \\ $$$${M}_{{D}} =\frac{\mathrm{1}}{\mathrm{5}}×\left(\mathrm{450}+\mathrm{50}+\mathrm{300}\right) \\ $$$$=\mathrm{160}\:{KNmm}=\mathrm{160}\:{Nm} \\ $$
Commented by Tawa11 last updated on 13/Nov/21
$$\mathrm{Great}\:\mathrm{sir}. \\ $$