Question-159157

Question Number 159157 by physicstutes last updated on 13/Nov/21

Answered by mr W last updated on 13/Nov/21

Commented by mr W last updated on 13/Nov/21

l e t {A A}^{'} = 1

\Rightarrow {B B}^{'} = \frac{50}{450} \times 1 = \frac{1}{9}

\Rightarrow {C C}^{'} = {B B}^{'} = \frac{1}{9}

\Rightarrow {D D}^{'} = \frac{75}{300 + 75} \times \frac{1}{9} = \frac{1}{45}

P \times 1 = 9 \times \frac{1}{45}

\Rightarrow P = \frac{1}{5} K N

M_{D} = \frac{1}{5} \times (450 + 50 + 300)

= 160 K N m m = 160 N m

Commented by Tawa11 last updated on 13/Nov/21

Great sir .

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