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Question-159396




Question Number 159396 by quvonnn last updated on 16/Nov/21
Answered by som(math1967) last updated on 16/Nov/21
area of △BCE=Area of △ECF           =(1/2)×4×3=6 sq.unit  CM is bisector of ∠C   ∴((EM)/(MB)) =((EC)/(CB))=(3/4)  ((Ar△EMC)/(Ar △CMB))=(3/4)  ∴Ar. △EMC=(3/7)×6=((18)/7)sq unit  S=Ar.△EMF=6−((18)/7)=((24)/7)squnit ans
areaofBCE=AreaofECF=12×4×3=6sq.unitCMisbisectorofCEMMB=ECCB=34ArEMCArCMB=34Ar.EMC=37×6=187squnitS=Ar.EMF=6187=247squnitans
Commented by som(math1967) last updated on 16/Nov/21
Commented by Rasheed.Sindhi last updated on 16/Nov/21
area of △BCE=^(?) Area of △BCF  Area of △BCF=4×4×(1/2)=8unit^2
areaofBCE=?AreaofBCFAreaofBCF=4×4×12=8unit2
Commented by som(math1967) last updated on 16/Nov/21
typo sir it △ECF
typosiritECF
Commented by Avijit007 last updated on 16/Nov/21
yes.
yes.

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