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Question-159690




Question Number 159690 by 0731619 last updated on 20/Nov/21
Answered by MJS_new last updated on 21/Nov/21
very obviously the limit is +∞  check for x=5  (5^(5!) /((5!)^5 ))=(5^(120) /(120^5 ))=((≈10^(84) )/(≈10^(10) ))
$$\mathrm{very}\:\mathrm{obviously}\:\mathrm{the}\:\mathrm{limit}\:\mathrm{is}\:+\infty \\ $$$$\mathrm{check}\:\mathrm{for}\:{x}=\mathrm{5} \\ $$$$\frac{\mathrm{5}^{\mathrm{5}!} }{\left(\mathrm{5}!\right)^{\mathrm{5}} }=\frac{\mathrm{5}^{\mathrm{120}} }{\mathrm{120}^{\mathrm{5}} }=\frac{\approx\mathrm{10}^{\mathrm{84}} }{\approx\mathrm{10}^{\mathrm{10}} } \\ $$

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