Question Number 159828 by amin96 last updated on 21/Nov/21
Commented by Rasheed.Sindhi last updated on 21/Nov/21
Commented by Rasheed.Sindhi last updated on 21/Nov/21
$$\mathcal{T}{he}\:{both}\:{angles}\:{labled}\:{by}\:'{x}'\:{are} \\ $$$${congruent}\:{because}\:{they}'{re}\:{corresponding} \\ $$$${angles}.{But}\:{their}\:{value}\:{is}\:{not}\:{fixed} \\ $$$$\left({as}\:{sir}\:{mr}\:{W}\:{has}\:{said}\:{about}\:{your}\right. \\ $$$$\left.{previous}\:{version}\:{of}\:{the}\:{question}.\right) \\ $$
Commented by amin96 last updated on 21/Nov/21
$$ \\ $$no solution?
Commented by amin96 last updated on 21/Nov/21
$${yes}\:{i}\:{know} \\ $$
Commented by mr W last updated on 21/Nov/21
$${if}\:{you}\:{don}'{t}\:{understand}\:{the}\:{answer} \\ $$$${of}\:{somebody},\:{please}\:{tell}\:{where}\:{your} \\ $$$${problem}\:{is},\:{instead}\:{of}\:{posting}\:{the}\: \\ $$$${same}\:{question}\:{again}\:{and}\:{again}. \\ $$$${here}\:{is}\:{my}\:{explanation}\:{why}\:{the}\: \\ $$$${question}\:{is}\:{wrong}\:{or}\:{why}\:{it}\:{has}\:{no}\: \\ $$$${solution}: \\ $$$${see}\:{following}\:{diagram}. \\ $$$${with}\:{given}\:{conditions}\:{only}\:{the}\:{red} \\ $$$${part}\:{is}\:{defined}.\:{you}\:{can}\:{draw}\:{infinite} \\ $$$${many}\:{parallel}\:{lines},\:{such}\:{as}\:{the}\:{black} \\ $$$${ones},\:{the}\:{blue}\:{ones}\:{or}\:{the}\:{green}\:{ones}. \\ $$$${that}\:{means}\:{there}\:{is}\:{no}\:{unique} \\ $$$${solution}\:{for}\:{the}\:{angle}\:{between}\:{the} \\ $$$${parallel}\:{lines}\:{and}\:{the}\:{red}\:{base}\:{line}. \\ $$
Commented by mr W last updated on 21/Nov/21