Question Number 160102 by mkam last updated on 24/Nov/21
Commented by mkam last updated on 24/Nov/21
$${help}\:{me}\:{sir}\:{please}\: \\ $$
Answered by kaivan.ahmadi last updated on 25/Nov/21
$$\frac{\partial{z}}{\partial{x}}=\mathrm{2}{xe}^{{x}^{\mathrm{2}} } +\frac{\mathrm{1}}{{x}}\mid_{\left(\mathrm{1},\mathrm{2}\right)} =\mathrm{2}{e}+\mathrm{1} \\ $$$$\frac{\partial{z}}{\partial{y}}=\frac{\mathrm{1}}{{y}}\mid_{\left(\mathrm{1},\mathrm{2}\right)} =\frac{\mathrm{1}}{\mathrm{2}} \\ $$$$ \\ $$