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Question-160296




Question Number 160296 by mathlove last updated on 27/Nov/21
Commented by bobhans last updated on 27/Nov/21
          (3)^(3/(x+1))  = (3)^(2/x)  ⇔ 3x=2x+2 ; x=2
$$\:\:\:\:\:\:\:\:\:\:\left(\mathrm{3}\right)^{\frac{\mathrm{3}}{\mathrm{x}+\mathrm{1}}} \:=\:\left(\mathrm{3}\right)^{\frac{\mathrm{2}}{\mathrm{x}}} \:\Leftrightarrow\:\mathrm{3x}=\mathrm{2x}+\mathrm{2}\:;\:\mathrm{x}=\mathrm{2} \\ $$
Answered by Rasheed.Sindhi last updated on 27/Nov/21
(3^3 )^(1/(x+1))  =(3^2 )^(1/x)    3^(3/(x+1)) =3^(2/x)   (3/(x+1))=(2/x)  3x=2x+2  x=2
$$\sqrt[{{x}+\mathrm{1}}]{\mathrm{3}^{\mathrm{3}} }\:=\sqrt[{{x}}]{\mathrm{3}^{\mathrm{2}} }\: \\ $$$$\mathrm{3}^{\frac{\mathrm{3}}{{x}+\mathrm{1}}} =\mathrm{3}^{\frac{\mathrm{2}}{{x}}} \\ $$$$\frac{\mathrm{3}}{{x}+\mathrm{1}}=\frac{\mathrm{2}}{{x}} \\ $$$$\mathrm{3}{x}=\mathrm{2}{x}+\mathrm{2} \\ $$$${x}=\mathrm{2} \\ $$

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