Question Number 160544 by cortano last updated on 01/Dec/21
Commented by bobhans last updated on 01/Dec/21
$$\:\mathrm{A}=\sqrt{\mathrm{11}×\mathrm{10}×\mathrm{7}×\mathrm{8}}\:=\:\mathrm{4}\sqrt{\mathrm{385}} \\ $$$$\:\mathrm{R}=\frac{\sqrt{\mathrm{157}×\mathrm{166}×\mathrm{158}}}{\mathrm{16}\sqrt{\mathrm{385}}}\:=\:\frac{\sqrt{\mathrm{1029449}}}{\mathrm{8}\sqrt{\mathrm{385}}} \\ $$$$\:\mathrm{S}_{\mathrm{circle}} =\:\frac{\mathrm{1029449}\pi}{\mathrm{24640}} \\ $$
Commented by mr W last updated on 01/Dec/21
