Question Number 160910 by geron last updated on 09/Dec/21
Answered by blackmamba last updated on 09/Dec/21
$$\:\:\:\:\:\:\sqrt[{\mathrm{3}}]{{a}^{\mathrm{2}} }+\sqrt[{\mathrm{3}}]{{b}^{\mathrm{2}} }+\mathrm{1}+\mathrm{2}\sqrt[{\mathrm{3}}]{{ab}}−\mathrm{2}\sqrt[{\mathrm{3}}]{{a}}−\mathrm{2}\sqrt[{\mathrm{3}}]{{b}}\:=\:\mathrm{49}+\mathrm{20}\sqrt[{\mathrm{3}}]{\mathrm{6}} \\ $$$$ \\ $$
Commented by geron last updated on 09/Dec/21
$$??? \\ $$