Question Number 160950 by geron last updated on 09/Dec/21
Answered by mindispower last updated on 09/Dec/21
$${y}=\frac{\mathrm{2}{x}}{\mathrm{1}−{x}^{\mathrm{2}} },{x}=\frac{\mathrm{2}{z}}{\mathrm{1}−{z}^{\mathrm{2}} },{z}=\frac{\mathrm{2}{y}}{\mathrm{1}−{y}^{\mathrm{2}} } \\ $$$${just}\:{x}={tg}\left({a}\right),{y}={tg}\left({b}\right),{z}={tg}\left({c}\right) \\ $$$${withe}\:{tg}\left(\mathrm{2}{t}\right)=\frac{\mathrm{2}{tg}\left({t}\right)}{\mathrm{1}−{tg}^{\mathrm{2}} \left({t}\right)} \\ $$
Commented by geron last updated on 10/Dec/21
$${thank}\:{you} \\ $$