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Question-161444




Question Number 161444 by cortano last updated on 18/Dec/21
Commented by blackmamba last updated on 18/Dec/21
f(x)=3x−4⇒f(2016)=6044
f(x)=3x4f(2016)=6044
Commented by blackmamba last updated on 18/Dec/21
f(x)=ax+b   f(x^2 +x)=ax^2 +ax+b  2f(x^2 −3x+2)=2[(ax^2 −3ax+2a)+b]  f(x)+2f(x^2 −3x+2)=3ax^2 −5ax+4a+3b    { ((3a=9⇒a=3)),((4a+3b=0⇒3b=−12; b=−4)) :}  ∴ f(x)= 3x−4⇒f(2016)=6044  3×2016−4  6044.0
f(x)=ax+bf(x2+x)=ax2+ax+b2f(x23x+2)=2[(ax23ax+2a)+b]f(x)+2f(x23x+2)=3ax25ax+4a+3b{3a=9a=34a+3b=03b=12;b=4f(x)=3x4f(2016)=60443×201646044.0

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