Question-161866

Question Number 161866 by Tawa11 last updated on 23/Dec/21

Commented by mr W last updated on 23/Dec/21

\frac{B C}{10} = \frac{6}{6 + 9} \Rightarrow B C = 4

\frac{A C}{6} = \frac{7.5}{9} \Rightarrow A C = 5

\frac{A X}{6} = \frac{5 - A X}{4} \Rightarrow A X = 3 \Rightarrow X C = 5 - 3 = 2

Commented by Tawa11 last updated on 23/Dec/21

God bless you sir . I understand now .

Commented by mr W last updated on 23/Dec/21

{i t}^{'} s f i n e w h e n y o u u n d e r s t a n d n o w .

Answered by som(math1967) last updated on 23/Dec/21

\frac{A B}{A D} = \frac{B C}{D E} [B C ∥ D E ∴ △ A B C \sim △ A D E]

\frac{6}{15} = \frac{B C}{10} \Rightarrow B C = 4 c m

a g a i n B C ∥ D E

∴ \frac{A B}{B D} = \frac{A C}{C E}

\frac{6}{9} = \frac{A C}{7.5} \Rightarrow A C = 5 c m

B X i s b i s e c t o r o f ∠ A B C

∴ \frac{A X}{X C} = \frac{A B}{B C} = \frac{6}{4} = \frac{3}{2}

∴ A X : X C = 3 : 2

A C = 5 c m

∴ A X = \frac{3}{5} \times 5 = 3 c m a n s

X C = \frac{2}{5} \times 5 = 2 c m a n s

Commented by Tawa11 last updated on 23/Dec/21

God bless you sir

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